# Author: fi-le - https://fi-le.net
# Licenced under MIT - https://mit-license.org/

import random

tries = 1000000 # This quantifies the participant's patience
average = 0 # This average is the one we used in the above demonstration
average_n = 0 # This is the one we noted in the proof

results = []
for i in range(tries):
    sum = 0
    n = 0
    while sum < 1:
        n += 1
        sum += random.random()

    average += sum
    average_n += n
    # print(2 * sum) # Here we can print out each individual recorded sum.

average /= tries / 2
average_n /= tries
print(f"E is apparently {average}.")
print(f"E is also apparently {average_n}.")
print("Best estimate yet: 2.718228857942657")